There is no such thing as a new idea.
Everything is related to everything else.
| Syntax | Full Formula | Meaning |
|---|---|---|
x++ |
x = x + 1 |
Increase x by 1 |
x-- |
x = x - 1 |
Decrease x by 1 |
x += n |
x = x + n |
Increase x by n |
x -= n |
x = x - n |
Decrease x by n |
x *= n |
x = x * n |
Multiply x by n |
x /= n |
x = x / n |
Divide x by n |
x++ and x += n make x steadily increase, while x-- and x -= n make x steadily decrease.x *= n, when n **> 1** → x is multiplied by a value greater than 1 each time, creating amplifying growth.x *=** n, when 0 < **n < 1** → x becomes a fraction of its previous value each time, creating diminishing decay.x /=** n, when n **> 1** → x becomes smaller each time because it is divided by a value greater than 1, creating diminishing decay.
The center point is always (width/2, height/2), so its position changes when the width or height of the canvas changes, but it always stays in the center. This is a positive relationship because when the width or height increases, the x or y position of the center also increases proportionally. Instead of thinking of position as a fixed value, I can think of it as a relationship between variables. It is also a diminishing relationship because the center position changes by half the amount that the canvas dimension changes.
Canvas width = width
Canvas height = height
Canvas slope = height /width
Center X = width / 2
Center Y = height / 2
I drew this diagram to understand how the position and size of a rectangle can be related to the canvas. Instead of using fixed numbers, I can use width and height as variables. If the rectangle starts at (width/4, height/4) and its dimensions are width/2and height/2, its center will always be (width/2, height/2). This means that when the canvas becomes larger or smaller, the rectangle changes proportionally and stays in the center.
rect(width/4, height/4, width/2, height/2);
